ONE-TO-ONE LINEAR TRANSFORMATIONS
Linear Algebra Project
Objectives:
Use 'linalg' package of Maple
1. To find whether a linear transformation is one-to-one.
2. To find the inverse transformation whenever possible.
Required Information:
If A is an n x n square matrix and
Then
is one-to-one if the range of
is
This also means A is invertible.
If
is one-to-one then the inverse transformation is defined by
Solved Example 1:
Let A =
The transformation
is given by
=
- 2
+ 2
= 2
+
+
=
+
a) Determine whether
is one-to-one.
b) If
is one-to-one find
Solution:
a) First we check if A is invertible using the inverse command.
A =
> with(linalg):
> A := matrix([[1, -2, 2], [2, 1, 1], [1, 1, 0]]);
> Ainverse:=inverse(A);
b) The existence of the inverse
of A shows that T is one-to-one, and the range of T is
. In fact for any vector
w =
in
there is a pre-image
given by
w.
> w := matrix(3,1,[w1, w2, w3]);
> x= evalm(Ainverse&*(w));
The vector x is given by
=
Solved Example 2:
Let A =
is given by
=
+ 4
-
= 2
+7
+
=
+3
a) Show that
is not one-to-one.
b) Find all vectors x in
which are mapped onto the 0 vector.
(Note that: For a one-to-one
transformation
only the 0- vector is mapped onto 0
vector.
In other words Ax = 0 or A
=
has only the trivial solution
or the solution space of the
system of corresponding linear equations consists of
= 0,
= 0,
= 0
Solution:
(a) We check whether matrix A =
is
invertible.
> A:= matrix(3,3, [1,2,1,-2,1,4,7,4,-5]);
> inverse(A);
Error, (in inverse) singular matrix
This means matrix A is not invertible.
(b) Now we find all vector w in
which map onto the 0 vector.
We do this by finding the rref of the system Ax = 0 using the augmented matrix.
Ax = 0
or
=
> w := matrix(3,1,[0,0,0]);
> Aw := augment(A,w);
> Awreduced:= rref(Aw);
This means that the solution
space consists of vectors
where
=
,
=
or all vectors
where
is a scalar.
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Assignment
In each of the problems for the matrix A
a) define
.
b) determine whether
is one-to-one.
c) if
is one-to-one find the inverse transformation. If
is not one-to-one find all the vectors which map onto the 0 vector.
Problem 1:
A =
Problem 2:
A =
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MSIP Grant #P120A80089-98: "Three Urban Calculus Reform programs: Adopting the Best" 1998-2001, MSEIP Grant #P120A010031: "Four Colleges: Calculus + Enhancements" 2001-04