{VERSION 5 0 "IBM INTEL NT" "5.0" } {USTYLETAB {CSTYLE "Maple Input" -1 0 "Courier" 0 1 255 0 0 1 0 1 0 0 1 0 0 0 0 1 }{CSTYLE "2D Math" -1 2 "Times" 0 1 0 0 0 0 0 0 2 0 0 0 0 0 0 1 }{CSTYLE "2D Comment" 2 18 "" 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 1 } {CSTYLE "2D Output" 2 20 "" 0 1 0 0 255 1 0 0 0 0 0 0 0 0 0 1 } {CSTYLE "" -1 256 "" 1 12 0 0 0 0 0 0 0 0 0 0 0 0 0 1 }{CSTYLE "" -1 257 "" 1 12 0 0 0 0 0 0 0 0 0 0 0 0 0 1 }{CSTYLE "" -1 258 "" 1 12 0 0 0 0 0 0 0 0 0 0 0 0 0 1 }{CSTYLE "" -1 259 "" 1 12 0 0 0 0 0 0 0 0 0 0 0 0 0 1 }{CSTYLE "" -1 260 "" 1 12 0 0 0 0 1 0 0 0 0 0 0 0 0 1 } {CSTYLE "" -1 261 "" 1 12 0 0 0 0 0 0 0 0 0 0 0 0 0 1 }{CSTYLE "" -1 262 "" 1 12 0 0 0 0 0 0 0 0 0 0 0 0 0 1 }{CSTYLE "" -1 263 "" 1 12 0 0 0 0 1 0 0 0 0 0 0 0 0 1 }{CSTYLE "" -1 264 "" 0 1 0 0 0 0 1 0 0 0 0 0 0 0 0 1 }{CSTYLE "" -1 265 "" 1 12 0 0 0 0 0 0 0 0 0 0 0 0 0 1 } {CSTYLE "" -1 266 "" 1 12 0 0 0 0 0 0 0 0 0 0 0 0 0 1 }{PSTYLE "Normal " -1 0 1 {CSTYLE "" -1 -1 "Times" 1 12 0 0 0 1 2 2 2 2 2 2 1 1 1 1 }1 1 0 0 0 0 1 0 1 0 2 2 0 1 }{PSTYLE "Heading 1" -1 3 1 {CSTYLE "" -1 -1 "Times" 1 18 0 0 0 1 2 1 2 2 2 2 1 1 1 1 }1 1 0 0 8 4 1 0 1 0 2 2 0 1 }{PSTYLE "Heading 2" -1 4 1 {CSTYLE "" -1 -1 "Times" 1 14 0 0 0 1 2 1 2 2 2 2 1 1 1 1 }1 1 0 0 8 2 1 0 1 0 2 2 0 1 }{PSTYLE "Warning" -1 7 1 {CSTYLE "" -1 -1 "Courier" 1 10 0 0 255 1 2 2 2 2 2 1 1 1 3 1 } 1 1 0 0 0 0 1 0 1 0 2 2 0 1 }{PSTYLE "Error" -1 8 1 {CSTYLE "" -1 -1 " Courier" 1 10 255 0 255 1 2 2 2 2 2 1 1 1 3 1 }1 1 0 0 0 0 1 0 1 0 2 2 0 1 }{PSTYLE "Maple Output" -1 11 1 {CSTYLE "" -1 -1 "Times" 1 12 0 0 0 1 2 2 2 2 2 2 1 1 1 1 }3 3 0 0 0 0 1 0 1 0 2 2 0 1 }{PSTYLE "Headi ng 1" -1 256 1 {CSTYLE "" -1 -1 "Times" 1 18 0 0 0 1 2 1 2 2 2 2 1 1 1 1 }3 1 0 0 8 4 1 0 1 0 2 2 0 1 }{PSTYLE "Heading 1" -1 257 1 {CSTYLE "" -1 -1 "Times" 1 18 0 0 0 1 2 1 2 2 2 2 1 1 1 1 }3 1 0 0 8 4 1 0 1 0 2 2 0 1 }} {SECT 0 {PARA 256 "" 0 "" {TEXT -1 33 "One-to-One Linear Transformatio ns" }}{PARA 0 "" 0 "" {TEXT -1 0 "" }}{PARA 4 "" 0 "" {TEXT -1 32 "Lin ear Algebra Project " }}{SECT 0 {PARA 3 "" 0 "" {TEXT -1 0 " " }{TEXT 256 12 " Objectives:" }}{PARA 0 "" 0 "" {TEXT -1 29 "Use 'lin alg' package of Maple" }}{PARA 0 "" 0 "" {TEXT -1 58 "1. To find whet her a linear transformation is one-to-one." }}{PARA 0 "" 0 "" {TEXT -1 57 "2. To find the inverse transformation whenever possible." }}} {SECT 0 {PARA 3 "" 0 "" {TEXT -1 0 "" }{TEXT 257 21 "Required Informat ion:" }}{PARA 0 "" 0 "" {TEXT -1 36 "If A is an n x n square matrix a nd " }{XPPEDIT 18 0 "T[A];" "6#&%\"TG6#%\"AG" }{TEXT -1 2 ": " } {XPPEDIT 18 0 "R^n;" "6#)%\"RG%\"nG" }{TEXT -1 6 " -> " }{XPPEDIT 18 0 "R^n" "6#)%\"RG%\"nG" }{TEXT -1 25 " is multiplication by A " }} {PARA 0 "" 0 "" {TEXT -1 8 " Then " }}{PARA 0 "" 0 "" {TEXT -1 2 " \+ " }{XPPEDIT 18 0 "T[A]" "6#&%\"TG6#%\"AG" }{TEXT -1 31 " is one-to-one if the range of " }{XPPEDIT 18 0 "T[A]" "6#&%\"TG6#%\"AG" }{TEXT -1 4 " is " }{XPPEDIT 18 0 "R^n;" "6#)%\"RG%\"nG" }}{PARA 0 "" 0 "" {TEXT -1 35 "This also means A is invertible. " }}{PARA 0 "" 0 "" {TEXT -1 4 "If " }{XPPEDIT 18 0 "T[A]" "6#&%\"TG6#%\"AG" }{TEXT -1 61 " is one-to-one then the inverse transformation is defined by " } {XPPEDIT 18 0 "T[A^(-1)];" "6#&%\"TG6#)%\"AG,$\"\"\"!\"\"" }{TEXT -1 10 " " }}}{SECT 0 {PARA 3 "" 0 "" {TEXT -1 0 "" }{TEXT 258 17 "Solved Example 1:" }}{PARA 0 "" 0 "" {TEXT -1 8 "Let A = " } {XPPEDIT 18 0 "matrix([[1, -2, 2], [2, 1, 1], [1, 1, 0]]);" "6#-%'matr ixG6#7%7%\"\"\",$\"\"#!\"\"F*7%F*F(F(7%F(F(\"\"!" }{TEXT -1 0 "" }} {PARA 0 "" 0 "" {TEXT -1 19 "The transformation " }}{PARA 0 "" 0 "" {TEXT -1 2 " " }{XPPEDIT 18 0 "T[A]" "6#&%\"TG6#%\"AG" }{TEXT -1 14 " is given by " }{XPPEDIT 18 0 "w[1];" "6#&%\"wG6#\"\"\"" }{TEXT -1 4 " = " }{XPPEDIT 18 0 "x[1];" "6#&%\"xG6#\"\"\"" }{TEXT -1 4 " - 2" } {XPPEDIT 18 0 "x[2];" "6#&%\"xG6#\"\"#" }{TEXT -1 4 " + 2" }{XPPEDIT 18 0 "x[3];" "6#&%\"xG6#\"\"$" }{TEXT -1 0 "" }}{PARA 0 "" 0 "" {TEXT -1 27 " " }{XPPEDIT 18 0 "w[2];" "6#&%\"wG6# \"\"#" }{TEXT -1 5 " = 2" }{XPPEDIT 18 0 "x[1];" "6#&%\"xG6#\"\"\"" } {TEXT -1 3 " + " }{XPPEDIT 18 0 "x[2];" "6#&%\"xG6#\"\"#" }{TEXT -1 3 " + " }{XPPEDIT 18 0 "x[3];" "6#&%\"xG6#\"\"$" }{TEXT -1 0 "" }}{PARA 0 "" 0 "" {TEXT -1 27 " " }{XPPEDIT 18 0 "w[ 3];" "6#&%\"wG6#\"\"$" }{TEXT -1 4 " = " }{XPPEDIT 18 0 "x[1];" "6#&% \"xG6#\"\"\"" }{TEXT -1 3 " + " }{XPPEDIT 18 0 "x[2];" "6#&%\"xG6#\"\" #" }{TEXT -1 1 " " }}{PARA 0 "" 0 "" {TEXT -1 21 "a) Determine whether " }{XPPEDIT 18 0 "T[A]" "6#&%\"TG6#%\"AG" }{TEXT -1 15 " is one-to-on e." }}{PARA 0 "" 0 "" {TEXT -1 7 " b) If " }{XPPEDIT 18 0 "T[A];" "6#& %\"TG6#%\"AG" }{TEXT -1 21 " is one-to-one find " }{XPPEDIT 18 0 "T[A ^(-1)];" "6#&%\"TG6#)%\"AG,$\"\"\"!\"\"" }}}{SECT 0 {PARA 3 "" 0 "" {TEXT -1 0 "" }{TEXT 259 1 " " }{TEXT 260 9 "Solution:" }}{PARA 0 "" 0 "" {TEXT -1 63 "a) First we check if A is invertible using the inver se command." }}{PARA 0 "" 0 "" {TEXT -1 6 " A = " }{XPPEDIT 18 0 "mat rix([[1, -2, 2], [2, 1, 1], [1, 1, 0]]);" "6#-%'matrixG6#7%7%\"\"\",$ \"\"#!\"\"F*7%F*F(F(7%F(F(\"\"!" }{TEXT -1 2 " " }}{EXCHG {PARA 0 "> \+ " 0 "" {MPLTEXT 1 0 13 "with(linalg):" }}{PARA 7 "" 1 "" {TEXT -1 80 " Warning, the protected names norm and trace have been redefined and un protected\n" }}}{PARA 0 "" 0 "" {TEXT -1 0 "" }}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 49 "A := matrix([[1, -2, 2], [2, 1, 1], [1, 1, 0]]); \+ " }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%\"AG-%'matrixG6#7%7%\"\"\"!\"#\" \"#7%F,F*F*7%F*F*\"\"!" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 21 "A inverse:=inverse(A);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%)AinverseG-% 'matrixG6#7%7%\"\"\"!\"#\"\"%7%!\"\"\"\"#!\"$7%F.\"\"$!\"&" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 89 "b) The existence of the inverse of A sho ws that T is one-to-one, and the range of T is " }{XPPEDIT 18 0 "R^3; " "6#*$%\"RG\"\"$" }{TEXT -1 26 ". In fact for any vector " }}{PARA 0 "" 0 "" {TEXT -1 5 " w = " }{XPPEDIT 18 0 "matrix([[w1], [w2], [w3]] );" "6#-%'matrixG6#7%7#%#w1G7#%#w2G7#%#w3G" }{TEXT -1 5 " in " } {XPPEDIT 18 0 "R^3" "6#*$%\"RG\"\"$" }{TEXT -1 23 " there is a pre-ima ge " }{XPPEDIT 18 0 "matrix([[x1], [x2], [x3]]);" "6#-%'matrixG6#7%7# %#x1G7#%#x2G7#%#x3G" }{TEXT -1 10 " given by " }{XPPEDIT 18 0 "A^(-1); " "6#)%\"AG,$\"\"\"!\"\"" }{TEXT -1 2 "w." }}{PARA 0 "" 0 "" {TEXT -1 0 "" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 31 "w := matrix(3,1,[w1, w2, w3]); " }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%\"wG-%'matrixG6#7%7#% #w1G7#%#w2G7#%#w3G" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 24 "x= ev alm(Ainverse&*(w));" }{TEXT -1 0 "" }}{PARA 11 "" 1 "" {XPPMATH 20 "6# /%\"xG-%'matrixG6#7%7#,(%#w1G\"\"\"*&\"\"#F,%#w2GF,!\"\"*&\"\"%F,%#w3G F,F,7#,(F+F0*&F.F,F/F,F,*&\"\"$F,F3F,F07#,(F+F0*&F8F,F/F,F,*&\"\"&F,F3 F,F0" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 11 "The vector " }{TEXT 264 1 "x" }{TEXT -1 22 " is given by " }{XPPEDIT 18 0 "matrix([[x 1], [x2], [x3]]);" "6#-%'matrixG6#7%7#%#x1G7#%#x2G7#%#x3G" }{TEXT -1 4 " = " }{XPPEDIT 18 0 "x = matrix([[w1-2*w2+4*w3], [-w1+2*w2-3*w3], \+ [-w1+3*w2-5*w3]]);" "6#/%\"xG-%'matrixG6#7%7#,(%#w1G\"\"\"*&\"\"#F,%#w 2GF,!\"\"*&\"\"%F,%#w3GF,F,7#,(F+F0*&F.F,F/F,F,*&\"\"$F,F3F,F07#,(F+F0 *&F8F,F/F,F,*&\"\"&F,F3F,F0" }{TEXT -1 4 " " }}}}{PARA 0 "" 0 "" {TEXT -1 1 " " }}{SECT 0 {PARA 3 "" 0 "" {TEXT -1 0 "" }{TEXT 261 18 " Solved Example 2:" }}{PARA 0 "" 0 "" {TEXT -1 9 " Let A = " } {XPPEDIT 18 0 "matrix([[1, 2, 1], [-2, 1, 4], [7, 4, -5]]);" "6#-%'mat rixG6#7%7%\"\"\"\"\"#F(7%,$F)!\"\"F(\"\"%7%\"\"(F-,$\"\"&F," }{TEXT -1 0 "" }}{PARA 0 "" 0 "" {TEXT -1 0 "" }}{PARA 0 "" 0 "" {TEXT -1 2 " " }{XPPEDIT 18 0 "T[A]" "6#&%\"TG6#%\"AG" }{TEXT -1 14 " is given b y " }{XPPEDIT 18 0 "w[1];" "6#&%\"wG6#\"\"\"" }{TEXT -1 4 " = " } {XPPEDIT 18 0 "x[1];" "6#&%\"xG6#\"\"\"" }{TEXT -1 4 " + 4" }{XPPEDIT 18 0 "x[2];" "6#&%\"xG6#\"\"#" }{TEXT -1 3 " - " }{XPPEDIT 18 0 "x[3]; " "6#&%\"xG6#\"\"$" }{TEXT -1 0 "" }}{PARA 0 "" 0 "" {TEXT -1 26 " \+ " }{XPPEDIT 18 0 "w[2];" "6#&%\"wG6#\"\"#" } {TEXT -1 5 " = 2" }{XPPEDIT 18 0 "x[1];" "6#&%\"xG6#\"\"\"" }{TEXT -1 3 " +7" }{XPPEDIT 18 0 "x[2];" "6#&%\"xG6#\"\"#" }{TEXT -1 3 " + " }{XPPEDIT 18 0 "x[3];" "6#&%\"xG6#\"\"$" }{TEXT -1 0 "" }}{PARA 0 "" 0 "" {TEXT -1 27 " " }{XPPEDIT 18 0 "w[3];" "6#&%\"wG6#\"\"$" }{TEXT -1 4 " = " }{XPPEDIT 18 0 "x[1];" "6#&%\"xG6 #\"\"\"" }{TEXT -1 3 " +3" }{XPPEDIT 18 0 "x[3];" "6#&%\"xG6#\"\"$" } {TEXT -1 1 " " }}{PARA 0 "" 0 "" {TEXT -1 15 " a) Show that " } {XPPEDIT 18 0 "T[A]" "6#&%\"TG6#%\"AG" }{TEXT -1 19 " is not one-to-on e." }}{PARA 0 "" 0 "" {TEXT -1 28 " b) Find all vectors x in " } {XPPEDIT 18 0 "R^3;" "6#*$%\"RG\"\"$" }{TEXT -1 36 " which are mapped \+ onto the 0 vector." }}{PARA 0 "" 0 "" {TEXT -1 44 "(Note that: For a o ne-to-one transformation " }{XPPEDIT 18 0 "T[A]" "6#&%\"TG6#%\"AG" } {TEXT -1 46 " only the 0- vector is mapped onto 0 vector. " }}{PARA 0 "" 0 "" {TEXT -1 26 "In other words Ax = 0 or A" }{XPPEDIT 18 0 "mat rix([[x[1]], [x[2]], [x[3]]]);" "6#-%'matrixG6#7%7#&%\"xG6#\"\"\"7#&F) 6#\"\"#7#&F)6#\"\"$" }{TEXT -1 3 " = " }{XPPEDIT 18 0 "matrix([[0], [0 ], [0]]);" "6#-%'matrixG6#7%7#\"\"!7#F(7#F(" }{TEXT -1 31 " has only t he trivial solution " }}{PARA 0 "" 0 "" {TEXT -1 82 "or the solution s pace of the system of corresponding linear equations consists of " } {XPPEDIT 18 0 "x[1];" "6#&%\"xG6#\"\"\"" }{TEXT -1 5 "= 0, " } {XPPEDIT 18 0 "x[2];" "6#&%\"xG6#\"\"#" }{TEXT -1 5 "= 0, " }{XPPEDIT 18 0 "x[3];" "6#&%\"xG6#\"\"$" }{TEXT -1 3 "= 0" }}}{SECT 0 {PARA 3 " " 0 "" {TEXT -1 0 "" }{TEXT 262 0 "" }{TEXT 263 10 " Solution:" }} {PARA 0 "" 0 "" {TEXT -1 32 "(a) We check whether matrix A = " } {XPPEDIT 18 0 "matrix([[1, 2, 1], [-2, 1, 4], [7, 4, -5]]);" "6#-%'mat rixG6#7%7%\"\"\"\"\"#F(7%,$F)!\"\"F(\"\"%7%\"\"(F-,$\"\"&F," }{TEXT -1 15 " is invertible." }}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 39 "A: = matrix(3,3, [1,2,1,-2,1,4,7,4,-5]);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%\"AG-%'matrixG6#7%7%\"\"\"\"\"#F*7%!\"#F*\"\"%7%\"\"(F.!\"&" }}} {EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 11 "inverse(A);" }}{PARA 8 "" 1 "" {TEXT -1 36 "Error, (in inverse) singular matrix\n" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 40 "This means matrix A is not invertible. " }}{PARA 0 "" 0 "" {TEXT -1 1 " " }}}{PARA 0 "" 0 "" {TEXT -1 32 "(b) Now we find all vector w in " }{XPPEDIT 18 0 "R^3" "6#*$%\"RG\"\"$" } {TEXT -1 31 " which map onto the 0 vector. " }}{PARA 0 "" 0 "" {TEXT -1 81 "We do this by finding the rref of the system Ax = 0 using the \+ augmented matrix. " }}{PARA 0 "" 0 "" {TEXT -1 41 " \+ Ax = 0 " }}{PARA 0 "" 0 "" {TEXT -1 6 "or " } {XPPEDIT 18 0 "matrix([[1, 2, 1], [-2, 1, 4], [7, 4, -5]]);" "6#-%'mat rixG6#7%7%\"\"\"\"\"#F(7%,$F)!\"\"F(\"\"%7%\"\"(F-,$\"\"&F," }{TEXT -1 1 " " }{XPPEDIT 18 0 "matrix([[x1], [x2], [x3]]);" "6#-%'matrixG6#7 %7#%#x1G7#%#x2G7#%#x3G" }{TEXT -1 3 " = " }{XPPEDIT 18 0 "matrix([[0], [0], [0]]);" "6#-%'matrixG6#7%7#\"\"!7#F(7#F(" }}{PARA 0 "" 0 "" {TEXT -1 0 "" }}{PARA 0 "" 0 "" {TEXT -1 3 " " }}{EXCHG {PARA 0 "> \+ " 0 "" {MPLTEXT 1 0 25 "w := matrix(3,1,[0,0,0]);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%\"wG-%'matrixG6#7%7#\"\"!F)F)" }}}{EXCHG {PARA 0 "> \+ " 0 "" {MPLTEXT 1 0 19 "Aw := augment(A,w);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#AwG-%'matrixG6#7%7&\"\"\"\"\"#F*\"\"!7&!\"#F*\"\"%F, 7&\"\"(F/!\"&F," }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 21 "Awreduce d:= rref(Aw);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%*AwreducedG-%'matri xG6#7%7&\"\"\"\"\"!#!\"(\"\"&F+7&F+F*#\"\"'F.F+7&F+F+F+F+" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 55 "This means that the solution space consis ts of vectors " }{XPPEDIT 18 0 "matrix([[x[1]], [x[2]], [x[3]]]);" "6# -%'matrixG6#7%7#&%\"xG6#\"\"\"7#&F)6#\"\"#7#&F)6#\"\"$" }{TEXT -1 7 " \+ where " }{XPPEDIT 18 0 "x[1];" "6#&%\"xG6#\"\"\"" }{TEXT -1 3 " = " } {XPPEDIT 18 0 "7*x[3]/5;" "6#*(\"\"(\"\"\"&%\"xG6#\"\"$F%\"\"&!\"\"" } {TEXT -1 2 ", " }{XPPEDIT 18 0 "x[2];" "6#&%\"xG6#\"\"#" }{TEXT -1 3 " = " }{XPPEDIT 18 0 "6*x[3]/5;" "6#*(\"\"'\"\"\"&%\"xG6#\"\"$F%\"\"&! \"\"" }{TEXT -1 0 "" }}{PARA 0 "" 0 "" {TEXT -1 17 "or all vectors \+ " }{XPPEDIT 18 0 "lambda;" "6#%'lambdaG" }{XPPEDIT 18 0 "matrix([[7/5] , [6/5], [1]]);" "6#-%'matrixG6#7%7#*&\"\"(\"\"\"\"\"&!\"\"7#*&\"\"'F* F+F,7#F*" }{TEXT -1 8 " where " }{XPPEDIT 18 0 "lambda;" "6#%'lambdaG " }{TEXT -1 13 " is a scalar." }}}}{PARA 0 "" 0 "" {TEXT -1 74 "______ ____________________________________________________________________" }}{PARA 257 "" 0 "" {TEXT -1 10 "ASSIGNMENT" }}{PARA 0 "" 0 "" {TEXT -1 41 "In each of the problems for the matrix A " }}{PARA 0 "" 0 "" {TEXT -1 11 " a) define " }{XPPEDIT 18 0 "T[A]" "6#&%\"TG6#%\"AG" } {TEXT -1 1 "." }}{PARA 0 "" 0 "" {TEXT -1 22 " b) determine whether " }{XPPEDIT 18 0 "T[A]" "6#&%\"TG6#%\"AG" }{TEXT -1 15 " is one-to-one. " }}{PARA 0 "" 0 "" {TEXT -1 7 " c) if " }{XPPEDIT 18 0 "T[A];" "6#&% \"TG6#%\"AG" }{TEXT -1 54 " is one-to-one find the inverse transforma tion. If " }{XPPEDIT 18 0 "T[A]" "6#&%\"TG6#%\"AG" }{TEXT -1 71 " is not one-to-one find all the vectors which map onto the 0 vector. " }}{PARA 0 "" 0 "" {TEXT -1 0 "" }}{SECT 0 {PARA 3 "" 0 "" {TEXT -1 1 " " }{TEXT 265 10 "Problem 1:" }}{PARA 0 "" 0 "" {TEXT -1 5 " A = " } {XPPEDIT 18 0 "matrix([[1, 3, -4], [2, 7, 1], [1, 3, 0]]);" "6#-%'matr ixG6#7%7%\"\"\"\"\"$,$\"\"%!\"\"7%\"\"#\"\"(F(7%F(F)\"\"!" }}}{PARA 0 "" 0 "" {TEXT -1 0 "" }}{PARA 0 "" 0 "" {TEXT -1 0 "" }}{SECT 0 {PARA 3 "" 0 "" {TEXT -1 1 " " }{TEXT 266 10 "Problem 2:" }}{PARA 0 "" 0 "" {TEXT -1 4 "A = " }{XPPEDIT 18 0 "matrix([[2, 0, -4], [2, 5, -1], [-1, 3, 0]]);" "6#-%'matrixG6#7%7%\"\"#\"\"!,$\"\"%!\"\"7%F(\"\"&,$\"\"\"F ,7%,$F0F,\"\"$F)" }}}{PARA 0 "" 0 "" {TEXT -1 77 "____________________ _________________________________________________________" }}{PARA 0 " " 0 "" {TEXT -1 172 "MSIP Grant #P120A80089-98: \"Three Urban Calculu s Reform programs: Adopting the Best\" 1998-2001, MSEIP Grant #P120A01 0031: \"Four Colleges: Calculus + Enhancements\" 2001-04" }}{PARA 0 " " 0 "" {TEXT -1 0 "" }}}{MARK "22 0" 97 }{VIEWOPTS 1 1 0 1 1 1803 1 1 1 1 }{PAGENUMBERS 0 1 2 33 1 1 }